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Determine the Average Dissipated Power at Watts in Re At 10khz

by Suleman
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Solution

At f=10 KHz

 

VoVs=​​ (SC1)RbrπRER2(1+gmrπ)SC1Rbrπ+RbrπRER2+βRER2+RErπ+R2rπ+1+SCeRe-RbRER2(1+gmrπ)

VoVs=​​ (2πj×10-1)1.75×10610.875×103(1+30)2πj×10-1×1.25×106+2.75×10310.875×103+326.65×103+145×103+(75×1031=j0.911-(30+1)(19.031×106)

VoVs=j3.706×105-74.14×103+j612.46×103=​​ j370.6-74.14+j612.46

VoVs=0.6007​​ 0.6 | 173.1

|Vo|= 0.6|Vs|

This circuit has the source voltage maximum (Vsm)=1V

Vom=0.6V​​  Vorms=​​ Vom2= 0.42V

Average power​​ dissipated in RE​​ is PRE​​ =​​ (Vorms)2 Re

PRE​​ =(0.42)2 175= 1.008×10-3

PRE​​ = 1.008MW

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